I am using jamovi to teach ANOVA and post-hoc.

When explaining the HSD test, I tell students that the Tukey test statistic is:

- Code: Select all
`t=(Mean_i - Mean_j)/sqrt(QME*(1/n_i+1/n_j) with N-k degrees of freedom`

I realize that the above statistic is not the Tukey-Cramer Q defined as

- Code: Select all
`Q=(Mean_i - Mean_j)/sqrt(QME/2*(1/n_i + 1/n_j)`

I guess that this would be ok if for t one used the t-distribution to find the p-value. However, I can't figure out what distribution jamovi is using (I also cheked SPSS and some question arise). I do however get the p-value that jamovi produces if I use Q and the qtukey distribution...

Can someone please clarify what formulae jamovi is using for the HSD Tukey's p-value?

Thanks in advance.

João