jamovi

Hi there,

I'm trying to compute a new variable that splits my data. When I try to split it using this : (FILTER(Cont_PostSum,Message=='Continuum')
it transforms my data from scale to ordinal, so I can't complete a one-way ANOVA to examine simple effects for my two-way repeated measures design.

Any tips?

Thanks

Anna

Hi, @bottlebrushpress.

If you want to be able to change the Measure type for your new variable, use Data> Transform.
First, select your variable to Transform (Cont_PostSum) which will be recognized in the filter function as $source and proceed by entering in the "recode condition" box:
FILTER($source, Message == 'Continuum')
Before exiting you can change the Measure type if the one assigned automatically does not correspond to the one of interest.

Cheers,
Maurizio

Brilliant. Thanks

Would you have any idea why I'm getting a message error saying 'factor consists of only one level'?

I'm trying to run a mixed ANOVA with a repeated measure on the second factor. I'm looking to examine whether opinions about schizophrenia change (and are stable over time pre-summary, post-summary, 3 weeks and 6 weeks), after participants have been presented with either a categorical definition of schizophrenia, or one that describes the condition as a continuum/spectrum. I selected a mixed ANOVA thinking it would be a 2 (message is either categorical or continuum) x 4 (time) with a repeated measure on the second factor. Within-subjects is time, between subjects is message. Does that sound about right?
The problem I'm having is that when I'm trying to split the data into 2 groups for simple effects/post hoc, it comes up with an error saying that my factor contains 'one level only', which I presume is the message factor. This factor should be continuum/symptoms (2 levels).
My concern is that maybe I'm running the wrong analysis? It wouldn't be a one-way analysis because there are two groups linked to the first factor, is that right?

take a look at all the different combinations of factor levels ... what you'll probably find is that you have empty cells in your design.

cheers

jonathon